Greenfoot

swap587

2013/9/8

#

Inspector ins = (Inspector)(getOneObjectAtOffset(0, 0 , Inspector.class)); ins.action(); - I am just trying to call a method of the class Inspector but unable to do it. Any suggestions. It does not give an error on compiling but gives error on run time.

JetLennit

2013/9/8

#

Try

Inspector ins = getOneObjectAtOffset(0, 0 , Inspector.class);

swap587

2013/9/8

#

It gives incompatible type error message...

JetLennit

2013/9/8

#

Could you give the entire class?

erdelf

2013/9/8

#

try

    
if(getOneObjectAtOffset(0,0,Inspector.class)!=null)
{
Inspector ins = (Inspector)getOneObjectAtOffset(0, 0 , Inspector.class);
ins.action();
}

Gevater_Tod4711

2013/9/8

#

@erdelf You should try not to call the same method two times if it's not neccessary. If you just check whether 'ins' is null you call the getOneObjectAtOffset method only one time which makes your code perform faster. Your code would also work and concerning the method getOneObjectAtOffset it wouldn't realy matter because the method has a very low runtime. But when you use methods with e.g. an exponential runtime it will mater.

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