Hey everyone! I want one actor to follow another. More specifically being in the same X Y coords as another actor. Also, if a button is not being pressed, the following actor goes offscreen automatically. Help would be appreciated! :D
Codybean1 wrote ...
2012/9/26
Having one Actor Follow Another? (No turning)
so you want one actor to move to the location of another actor every time?
this is simple.
You just have to get the reference to the actor.
Try this:
Of course you have to change the names a and b but then it should work.
public class A extends Actor {
private B b;
//some other variables and code;
public A(B b) {
this.b = b;
}
public void act() {
//follow actor b;
setLocation(b.getX(), b.getY());
}
}
public class B extends Actor {
...
//somewhere you have to add the object A to the world. So do this:
private A a = new A(this);//this chould be global;
getWorld().addObject(a, getX(), getY());//in a method or the construktor;
...
}I'm trying to implement it but I'm confused between the uppercase and lowercase a's and b's. Can you use weirder symbols " Squggly, Robot," so I'm not inputing it incorrectly? :D
If the Squggly object is to follow the Robot object and 'space' is the key then
// in the world class constructor
Squggly squggly = new Squggly;
Robot robot = new Robot(squggly);
// the rest is in the Robot class
// instance fields
Squggly squggly = null;
boolean squgglyShowing = false;
// the constructor
public Robot(Squggly squggly)
{
this.squggly = squggly;
}
// in the act method
checkSquggly();
// add the method
private void checkSquggly()
{
if (!squgglyShowing && Greenfoot.isKeyDown("space"))
{
getWorld().addObject(squggly, getX(), getY());
squgglyShowing = true;
}
if (squgglyShowing && !Greenfoot.isKeyDown("space"))
{
getWorld().removeObject(squggly);
squgglyShowing = false;
}
if (squgglyShowing) squggly.setLocation(getX(), getY());
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